[ Conica @ 11.03.2005. 00:29 ] @
Postovanje Imam sledeci kod: Code: $sql = MySql_Query("SELECT lt.translation, l.language_sign FROM language l, language_translation lt WHERE l.id = lt.id_language_translated AND lt.id_language_source = (SELECT id FROM language WHERE language_sign = '$language')") or die(mysql_error()); $result = MySql_Fetch_Array($sql); $num_results = MySql_Num_Rows($result); promenljiva $language nosi za ovaj primer predefinisanu vrednost "en". sql upit je testiran u bazi i vraca dva reda sa dva polja (language, sign): english en serbian sr na echo $result je array Javlja mi sledecu gresku: Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource KAKO!!!!! cheers cony |