[ skyforever @ 17.06.2010. 09:27 ] @
Pozdrav svima! Dugo nisam radio xslt, xpath i slicno, pa sada imam problem. Kreirao sam xml fajl koji ima sledecu strukturu Code (xml): <root> <checkup> <orderNumber>1</orderNumber> <organization>Organizacija 1<organization> <results> <result> <name>Marko Markovic</name> <disciplines> <discipline> <term>Prva disciplina</term> <res>18</res> <points>76</points> </discipline> <discipline> <term>Druga disciplina</term> <res>35</res> <points>80</points> </discipline> ------ </disciplines> </result> <result> <name>Nikola Nikolic</name> <disciplines> <discipline> <term>Prva disciplina</term> <res>44</res> <points>89</points> </discipline> <discipline> <term>Druga disciplina</term> <res>56</res> <points>98</points> </discipline> ------ </disciplines> </result> </results> </checkup> <checkup> <orderNumber>1</orderNumber> <organization>Organizacija 2<organization> <results> <result> <name>Petar Petrovic</name> <disciplines> <discipline> <term>Prva disciplina</term> <res>18</res> <points>76</points> </discipline> <discipline> <term>Druga disciplina</term> <res>35</res> <points>80</points> </discipline> ------ </disciplines> </result> <result> <name>Steva Stevanovic</name> <disciplines> <discipline> <term>Prva disciplina</term> <res>44</res> <points>89</points> </discipline> <discipline> <term>Druga disciplina</term> <res>56</res> <points>98</points> </discipline> ------ </disciplines> </result> </results> </checkup> </root> Hocu da pomocu xslt izaberem <results> na osnovu <orderNumber> i <organization> i da upisem u tabelu koju cu prikazati korisniku. Znaci, rezultati se prikazuju na osnovu naziva organizacije i rednog broja provere. Da li neko ima predlog? Hvala! [Ovu poruku je menjao mmix dana 17.06.2010. u 11:13 GMT+1] |