[ aleksandar.80 @ 09.06.2011. 10:40 ] @
| Imam jedan uredjaj za prijavljivanje i odjavljivanje zaposlenih. U sklopu njega dosao je i neki kineski program koji ne zadovoljava moje potrebe. Racunar sa uredjajem komunicira preko mreze (UDP). Koristio sam Wireshark da uhvatim saobracaj i tu je nastao problem. Interesuje me da li je ovo enkriptovano??? Zahtev koji racunar salje uredjaju: ..D..'...'..2....'....]..'... ...........\..'.......@....[R.' ..@[email protected].'!...........[..'"...N..'#. Deo odgovora (od uredjaja prema racunaru) ..o..'.....O.'..................:...............>...........................0u..P........t........$..'............DM...`..'...@.........>.............Yf.4....Yf.0....Yf.4....Zf.7....[f.,....`f.....8af.4...fcf.4.0..cf.6....df...0..df...0.Edf.,.0.Mdf.%...Nhf...0.`hf.!....hf.8.0..jf.4...V.f...0...f...0...f...0...f...0...f.0.....f.......g.6....yg......yg.,..._{g.....#|g.....c}g.9.....g.......g.......g.$.....g.".....g.0.....g.......g.4.....g.0...?.g.".0...g.9.0...g.9.....g.%...F.g.9.....g.2.....g.6.0...g...0.,.g...0.4.g...0.N.g...0...g...0...g.,.0...g.$.0...g. .....g.....r.g. .0...g.5.....g.......g...0. .g...0...g.......h.4.0..Lh.%.0..Oh. .0..Ph...0.rQh.4.....h.....P.h.%...X.h.#...].h.......h.......h.......h.......h.......h.....?.h.....F.h.....L.h.3.....h.'.....h.......h. ... .h.'.0.8$i.....$.i.9.....i....../i.4..../i...0.~0i...0..0i.%.0.72i...0..2i."....4i...0.#4i...0..5i...0..6i. .0..:i...0..:i...0..:i.1.0..:i.3.0..;i...0..Ci...0..Fi......ji...0.`ni......oi.9.0...i...0.=.i...0.W.i.".0...i...0...i.".....j.6.....j.......j.......j.&.....j.'.....j.$...H.j.....N.j.....X.j.2.....j.9.....j...... Unapred zahvalan |