[ Kraguj_KG @ 14.06.2016. 21:53 ] @
| Pozdrav svima! Trebala bi mi mala pomoc oko jednog projekta, pronasao sam ga na netu i bakcem se sa njime par dana... Kod je sledeci: //code modified for improvement from http://forum.arduino.cc/index.php?topic=8563.0 //connect pin 9 -> 10k Ohm + (series with)100nF ceramic cap -> GND, tap the sinewave signal from the point at between the resistor and cap. float wav1[3];//0 frequency, 1 unscaled amplitude, 2 is final amplitude int average; const int Pin = 9; float time; float percentage; float templitude; float offset = 2.5; // default value 2.5 volt as operating range voltage is 0~5V float minOutputScale = 0.0; float maxOutputScale = 5.0; const int resolution = 1; //this determines the update speed. A lower number means a higher refresh rate. const float pi = 3.14159; void setup() { wav1[0] = 50; //frequency of the sine wave wav1[1] = 2.5; // 0V - 2.5V amplitude (Max amplitude + offset) value must not exceed the "maxOutputScale" TCCR1B = TCCR1B & 0b11111000 | 1;//set timer 1B (pin 9) to 31250khz pinMode(Pin, OUTPUT); //Serial.begin(115200);//this is for debugging } void loop() { time = micros()% 1000000; percentage = time / 1000000; templitude = sin(((percentage) * wav1[0]) * 2 * pi); wav1[2] = (templitude * wav1[1]) + offset; //shift the origin of sinewave with offset. average = mapf(wav1[2],minOutputScale,maxOutputScale,0,255); analogWrite(9, average);//set output "voltage" delayMicroseconds(resolution);//this is to give the micro time to set the "voltage" } // function to map float number with integer scale - courtesy of other developers. long mapf(float x, float in_min, float in_max, long out_min, long out_max) { return (x - in_min) * (out_max - out_min) / (in_max - in_min) + out_min; } Sada, lepo sam povezao RC filter izmedju Pin 9 i GND ali posto nemam osciloskop da posmatram signal da li neko mozda ima predlog kako da preradim ovaj vec postojeci kod da prikazuje sinusoide npr. na serial monitoru (serial ploter)? Mozda je glupo pitanje ali posto sam pocetnik u ovome, svaka pomoc je dobrodosla :) Drugari, hvala unapred na pomoci! [Ovu poruku je menjao Kraguj_KG dana 14.06.2016. u 23:33 GMT+1] |