[ dejanc @ 12.08.2006. 19:15 ] @
Zdravo, pise vec da mi treba petlja koja ce mi obojiti svaki drugi red u drugu boju |
[ dejanc @ 12.08.2006. 19:15 ] @
[ noviKorisnik @ 12.08.2006. 19:34 ] @
Code: $par = 1; .. petlja .. $par = 1 - $par; echo "<tr class=\"stil$par\"> ... ... .. kraj petlje .. U css imaš 2 klase stil0 i stil1 i dadeš im da imaju različitu boju pozadine ... i to je to. [ pcaca @ 12.08.2006. 22:27 ] @
Pokusaj ovako (na pamet, nisam testirao):
Code: $count = 1; while ($rRow = mysql_fetch_row($result)) { $first = $rRow[1]; $second = $rRow[2]; $third = $rRow[3]; if ($count % 2) == 1) { echo "<li class='comment'>"; } else { echo "<li class='comment alt'>"; } echo "<span>"; echo "<div>$first</div>"; echo "<div>$second</div>"; echo "<div>$third</div>"; echo "</span>"; echo "</li>"; ++$count; } echo "</ol>"; [ sale83 @ 13.08.2006. 02:11 ] @
Code: $boja = "#FF0000"; echo '<table width="500 border="0" >'; while ($red = mysql_fetch_row($resulti)) { $boja = ($boja=='#FF0000' ? '#CCCCC' : '#FF0000'); echo '<tr bgcolor="'. $boja .'"> <td>Sve sto oces da ispises</td> </tr>'; } echo '</table>'; Isto mozes umesto $boja = "#FF0000"; da definises $class = "nekiclass"; ... dalje znas sta mislim.. Poz sale [ Br@nkoR @ 13.08.2006. 07:17 ] @
Ili samo css
Code: table tr:nth-child(2n) { background-color: #999; } table tr:nth-child(2n+1) { background-color: #666; } odnosno: Code: table tr:nth-child(even) { background-color: #999; } table tr:nth-child(odd) { background-color: #666; } Copyright (C) 2001-2025 by www.elitesecurity.org. All rights reserved.
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