[ djovan01 @ 04.01.2007. 18:04 ] @
Nesto ne valja ovde. A ne znam sta je. Pomozite. Kada ubacim id u search treba da mi izbaci odgovarajuci formular koji je promenjiv. od jednom u prvo polje gde bi trebalo da ubaci c_name ubaci id pa sve ostalo tako da output bude pomesan.

$hostname = "localhost";
$username= "leecontr_danijel";
$password= "*****";
$dbhandle = mysql_connect($hostname, $username, $password)
or die("Unable to connect to MySQL");
$selected = mysql_select_db("leecontr_betaquote",$dbhandle)
or die("Could not select quote");

$id = addslashes($_POST['q_id']);
$result = mysql_query("SELECT * FROM test WHERE q_id = '$id'");

list($c_name,$contact_name,$phone,$email,$j_location,$start_date,$hours,$ceiling_ht,$floor,$dock_yes,$dock_no,$dock_size,$ground_yes,$ground_no,$ground_size,$crane_yes,$crane_no,$crane_size,$b_manuf,$b_voltage,$b_amperage,$p_manuf,$p_voltage,$p_amperage,$amp_of_equipment,$distance,$machine_manuf,$serial,$weight,$ht,$wt,$lt,$p_address,$p_city,$p_state,$d_address,$d_city,$d_state,$additional,$soil_condition,$size,$cad_drawings_yes,$cad_drawings_no,$dimensions_from_wall,$pipe_size,$length,$material,$substance,$lifts_yes,$lifts_no,$lift_size,$scissors,$boom)=mysql_fetch_row($result);
echo" <form action='testinsert.php' method='post'>
<table width='560' border='1' class='styleForTable'>
<tr bgcolor='#999999'>
<td colspan='3' class='styleForTable'><div align='center'><strong><font color='#FF3300'>--- Quote
Request form ---</font></strong></div>
</td>
</tr>
<tr bgcolor='#CCCCCC'>
<td colspan='3' class='styleForTable'><strong><em><font color='#000000'>Contact
Information</font></em></strong></td>
</tr>
<tr>
<td width='208' class='styleForTable'>Company Name </td>
<td colspan='2' class='styleForTable'><input name='c_name' type='text' value='$c_name'>......
[ VladaSu @ 28.06.2007. 17:28 ] @
Mozda zato sto ti je id prva kolona u tabeli baze.

stavi

list($id,$c_name....