[ dinakay @ 07.10.2007. 23:15 ] @
Problem:
A school play ran for two nights, with audiences totaling 1390 adults and students. They paid $4285 for admission. One adult ticket cost $4.00 and one student ticket cost $2.50. The ratio of adults to students was 3: 5 on the first night and 2: 3 on the second night. How many students attended each night?


X= # of adults
Y= # of students


x + y =1390
4x + 2.5y =4285

4x + 4y =5560
4x + 2.5y =4285
1.5y =1275
y = 850

x + 850 =1390 - 850
- 850
X = 540

540 adults and 850 students...

X= # of adults on the first day
Y= # of students on the first day

x/y = 3/5
540 - x / 850 – y = 2/3

Kako dalje, ako moze pomoc?
[ Daniel011 @ 08.10.2007. 03:26 ] @
Pa sve si zapravo već rešio. Jedino što još treba da napišeš kao , pa kad to uvrstiš u drugu jednačinu, dobijaš , a to kad središ dobija se i .
[ dinakay @ 08.10.2007. 18:24 ] @
Oh hvala, ali zapravo sam *resila.
I htela sam da pitam, jer imam probleme sa basicnom aglebrom, jer znas neki site koji moze da pomogne s tim.
I isto, ako moze, da objasnis koji code ste koristili da napisete fractions tako...
hvala.
[ Daniel011 @ 08.10.2007. 19:14 ] @
Citat:
dinakay: I isto, ako moze, da objasnis koji code ste koristili da napisete fractions tako...

Ovde je sve objašnjeno:
http://www.elitesecurity.org/t35291