[ Neshonee @ 08.07.2011. 16:37 ] @
| Ljudi imam sad ovaj problem. Treba da iz odredjenog text fajla na osnovu unetog broja iz tog reda ispise neki broj u tom redu koji je uvek na istom mestu. U Text fajlu imam sledeci text: Code: insert into deonica (iddeonica,duzina,Vn,tip_voda,presek,Rd,Ri,Ro,Xd,Xi,Xo,Bd,Bi,Bo,Gd,Gi,Go,pocetak,kraj) values (4001,1,20,2,null,0.209,0.209,0.75,0.117,0.117,0.112,0.116,0.116,0.695,0,0,0,2001,5001) insert into deonica (iddeonica,duzina,Vn,tip_voda,presek,Rd,Ri,Ro,Xd,Xi,Xo,Bd,Bi,Bo,Gd,Gi,Go,pocetak,kraj) values (4002,2,20,2,null,0.209,0.209,0.75,0.117,0.117,0.112,0.116,0.116,0.695,0,0,0,5001,5002) insert into deonica (iddeonica,duzina,Vn,tip_voda,presek,Rd,Ri,Ro,Xd,Xi,Xo,Bd,Bi,Bo,Gd,Gi,Go,pocetak,kraj) values (4003,2.5,20,2,null,0.209,0.209,0.75,0.117,0.117,0.112,0.116,0.116,0.695,0,0,0,5002,5007) Ja na osnovu unete deonice koja ima iddeonica=4001 (znaci unosom broja 4001) treba da ispisem pocetak koji ima vrednost u redu 2001. Uz pomoc drugara sam uspeo da odradim sledeci kod, mislio sam da znam c++ dok nisam poceo da se bavim malo. Ovde pojedine naredbe ni ne razumem :/ Code: #include <iostream> #include <fstream> #include <map> #include <sstream> int main(int argc, char* argv[]) { if (argc != 2) { std::cerr << "Usage: test [inputfile]" << std::endl; return 1; } std::fstream stream(argv[1]); if (!stream.good()) { std::cerr << "Error: could not open file: " << argv[1] << std::endl; return 2; } std::string line; std::map<int, std::string> map; while (std::getline(stream, line)) { std::string::size_type pos = line.find(','); std::stringstream sstream(line.substr(0, pos)); int index; sstream >> index; map[index] = line.substr(pos+2); } int in; while (std::cin >> in) { std::map<int, std::string>::iterator i = map.find(in); if (i == map.end()) std::cerr << "index not found" << std::endl; else std::cout << i->second << std::endl; } return 0; } |