[ radulence84 @ 13.07.2011. 18:23 ] @
| Imam sledeci problem. Napisao sam kod koji bi trebalo da prihvati podatke iz forme i upise u tabelu ali nesto nece da radi Code: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <meta http-equiv="content-type" content="text/html; charset=utf-8" /> <meta name="description" content="" /> <meta name="keywords" content="" /> <meta name="author" content="" /> <link rel="stylesheet" type="text/css" href="style.css" media="screen" /> <title>1stWebDesigner PHP Template About Page</title> </head> <body> <div id="wrapper"> <?php include('includes/header.php'); ?> <?php include('includes/nav.php'); ?> <div id="content"> <?php if (isset($_POST['submit'])) { $con = mysql_connect("upisano ispravno","upisano ispravno","upisano ispravno"); // insert into table mysql_select_db("upisano ispravno", $con); $sql = "INSERT INTO vlasnici (vlasnikID, Ime, Prezime, Mesto, fixtel, mobtel, brojgrla) VALUES (NULL, '$_POST[ime]', '$_POST[prezime]', '$_POST[mesto]', '$_POST[fixtel]', '$_POST[mobtel]', '$_POST[brojgrla]')"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "Uspesno ste upisali korisnika u bazu podataka."; echo "Upisite novog korisnika"; mysql_close($con); } ?> <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> <p>Ime: <input type="text" name="ime"/></p> <p>Prezime: <input type="text" name="prezime"/></p> <p>Mesto: <input type="text" name="mesto"/></p> <p>Fiksni telefon: <input type="text" name="fixtel"/></p> <p>Mobilni telefon: <input type="text" name="mobtel"/></p> <p>Broj grla: <input type="text" name="brojgrla"/></p> <p><input type="submit" name="submit" value="Upisi"/></p> </form> </div> <!-- end #content --> <?php include('includes/sidebar.php'); ?> <?php include('includes/footer.php'); ?> </div> <!-- End #wrapper --> </body> </html> To nece da funkcionise ali kad odvojim php kod od forme sve radi. Gde gresim? |
