[ sjaker @ 08.06.2015. 19:30 ] @
Citam php manual i vidim nema slicna funkcija mysql_result.. mysqli_query($link, "SELECT user_id FROM 'users' WHERE ...") treba mi da na najprostiji nacin ispisem user_id ako je ispunjen uslov proceduralno.. |
[ sjaker @ 08.06.2015. 19:30 ] @
[ MPesic @ 10.06.2015. 03:53 ] @
Code (php): $result = mysqli_query($link, "SELECT user_id FROM users WHERE..."); $data = mysqli_fetch_assoc($result); echo $data['user_id']; ili za vise redova Code (php): $result = mysqli_query($link, "SELECT used_id FROM users WHERE..."); $data = mysqli_fetch_assoc($result); while($row = $data) { echo $row['user_id') . ""; }; Copyright (C) 2001-2025 by www.elitesecurity.org. All rights reserved.
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