Ideja 1: Koliko sam razumeo, u delu karakteristike OC ima konstantan CTR (Current Trasnsfer Ratio), pa bi, u strujnom domenu, OC trebao da je dovoljno linearan za male signale. Treba ti konvertor napona u struju na strani drajvera LED, a struje u napon na strani fototranzistora.

Ideja 2: Ucini kao sto svi cine, pa uradi PWM konverziju, prebaci impulse optokaplerom, isfiltriraj nosilac i eto...

Ideja 3: Nadji dva identicna (upari ih) OC, pa izlaz jednog vezi u kolo negativne povratne sprege neinvertujuceg pojacivaca sa operacionim pojacivacem, a izlaz drugog upotrebi za prenos signala na izolovanu stranu.

Puno hvala na idejama, ali mi je problem sto moram ocuvati fazu signala,
sinus manje vise, pa otpada PWM varijanta. Konkretno treba preneti i dalje
obraditi signal strujnog mernog i naponskog mernog transformatora, ali je
veoma sirok opseg amplituda cca 0.1 In do 20 In pa samim tim treba resiti
problem u delu kerakteristike diode OC koja je priblizno linearna. Mozda sam
dosadan, ali moram ovo da resim ma neki neki nacin. Zahvalan za pomoc.
Pozdrav.

Uh, mislim da ces svakako imati problem sa preciznoscu. Bolje bi bilo ako je moguce da svu obradu i merenje obavis sa one strane izolacione barijere, pa da preko optokaplera prebacis samo gotovu informaciju.

Inace, ako ti budzet nije problem, neki proizvodjaci prave (prilicno skupe, reda 100$) linearne optokaplere bas za te namene.

Nego, zar ti merni transformatori vec ne pruzaju dovoljnu izolaciju?

Salec puno hvala na interesovanju za temu, zaista mi je bitno da to
koncipiram i odradim. Radi se o sklopu koji bi trebao da bude interfejs
izmedju sekundara mernih transformatora / 100 V ili 5 A / i inteligentne
zastite mreze ili potrosaca sa svim opcijama i pracenjem velicina / fazne i
linijske struje i naponi, fazni stavovi, izoblicenje sinusa /,
najverovatnije sa odgovarajucim PIC / najverovatnije PIC16F877, zbog
dovoljnog broja I/O i D/A konverzije /. U celoj prici moj posao je da "samo"
po zahtevu energeticara koncipiram i razradim mehaniku, elektroniku i sminku
kao i projektni zadatak za izradu softvera, sto bi radio onaj ko zna. Sve je
to u fazi razmisljanja ali mislim da mi problem predstavlja prenos ciste
naponske informacije sa razdelnika na sekundaru mernog transformatora sa
ocuvanom fazom do ulaza u kontroler. Sto se tice izolacije sekundara, ona je
svakako dovoljna, ali mislim da je suvise optimisticki smatrati da nece biti
izvesnih smetnji elektromagnetne i elektrostaticke prirode posto se radi o
gomili opreme u neposrednoj blizini, a zbog kasnjenja je upitna neka
narocita upotreba filterskih elemenata. Zbog toga mislim da je najbezbolnije
resenje da koristim samo razdelnik napona pre OC, a posle taj signal koji
ima ocuvanu fazu i srazmernu amplitudu nekako cistiti pre kontrolera, ili
cak softverski resiti da "kontroler" ne vidi ono sto ne treba da vidi.
Inace, mozda bi bila zanimljiva / jer je najlakse ostvariva / ideja sa tim
linearnim OC, samo ako imas oznaku ili ideju koja trgovina to ima. Normalno
je da su troskovi limitirani, ali moram da dam resenje. Ti pomenu onu vezu
sa dva OC i dva OP, ja tu semu negde imam ali sam skeptican da bi se na taj
nacin kvalitetno promena ulazne informacije spakovala u koristan deo
karakteristike diode OC. Mozda ne shvatam rad tog sklopa. Ti pomenu i
preciznost, zasto kada je u pitanju 50 Hz, sto nije neka brzina? Pozdrav.

To sa dva OC je neka moja izmisljotina, ako se neko vec ne javi da je njegova :). Naime, prvo zamisli servopetlju sa op-amp -om gde je LED OC-a, preko otpornika za ogranicenje struje, vezan izmedju izlaza opamp i (-) napajanja, a aktuator koji regulise izlazni napon je tranzistor OC-a koji je vezan na primer kao emiter-follower na (+) napajanja. Zamisli da vracas napon sa emitera, odnosno emiterskog otpornika (drugi kraj otpornika je na (-) ), na inv. ulaz opampa. Kao sto vidis, imas jednu servo-petlju koja tera napon na emiterskom otporniku da strogo prati napon na neinvertujucem ulazu opampa.

E sad, ako uzmes drugi, odabrani upareni ("identicni") OC i vezes njegov LED u seriju sa onim prvim LED, a na izolovanoj strani kreiras identicno izlazno kolo, moje predvidjanje je da ces imati vrlo malu razliku izmedju napona na izlazu na toj izolovanoj strani i napona na izlazu na "predajnoj strani", i to u sirokom dinamickom opsegu, pod uslovom da opterecenje tog sklopa na "izolovanoj strani" ne bude vece od onog na predajnoj (znaci, treba staviti odvojni voltagefollower sa jos jednim opampom).

Moguca je i varijanta sa simetricnim napajanjem i dva para OC... slicno pushpull ili totem-pole konfiguracijama.



Potrazi ko zastupa Agilent, nekadasnji Hewlett Packard, tu kod tebe.

Verujem da ti je ideja dobra, ali mislim da bi razvoj toga bio malo ili
malo vise komplikovan i dugotrajan. Nego sta mislis o ovom resenju / attach
/, nije mi jasno zasto je autor koristio +/- napajanje kada i onako ne moze
da prenese ceo sinus zbog karakteristike OC diode. U ovoj varijanti bi bila
prenesena jedna poluperioda a druga identicnim sklopom samo sa drugacijim
polarizacijama. Sta mislis o tome? Koje bi koristio OP, s obzirom na to da
bi eventualna dogradnja kontrole nule komplikovala stvar i verovatno
zahtevala temperaturnu kompezaciju? Pozdrav.

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Ne vidim semu...

Ako bas insistiras na optokaplerima, rasmisli o par problema, npr. kako ces precizno preneti jednosmernu komponentu mernog signala?

Pre ili kasnije ces morati da radis A/D konverziju. Sto pre to bolje. Kako mislis da radis istu bez antialiasing filtra?
Potrazi Analog Devices Application Note 639 (AN-639).

Salec, evo je sema u predhodnom odgovoru.

Blazo, meni treba da prenesem sinus i da ga na drugoj strani imam sa
ocuvanom fazom i srazmernom amplitudom. Znaci u mernom signalu nemam
jednosmernu komponentu. Sto se tice A/D konverzije, ne moze se vrsiti nigde
pre jer mi na ovoj strani treba i anlogni signal sa pomenutim osobinama i on
ce verovatno biti cca 15-20 Vpp, pa ce se razdelnikom smanjiti na nivo za
A/D konverziju. Pod predpostavkom da se koriste 2X2 OC, zbog pozitivne i
negativne poluperiode, na koje probleme mislis? Sta mislis o ovom nacinu /
sema u predhodnom odgovoru /?

Nemam ni vremena ni energije da detaljnije analiziram semu. Pokusaj da shvatis kako sklop radi. Optokaplere aproksimiraj tako sto ces LE diode zameniti sa idealnim naponskim generatorima napona 1.7V, a fototranzistore idealnim strujnim izvorima struje k * struja kroz LE diodu. Iz prvog dela sklopa se vidi da ce struja kroz LE diodu prvog optokaplera biti 0,0012(1/ohm) * Vin + 3.0 mA. Znaci, kada je Vin = 0.0V, struja kroz LE diodu optokaplera je 3.0 mA. Sa porastom Vin raste i struja, i obrnuto. Nisu ti potrebna dva sklopa (za pozitivne i negativne poluperiode). Upravo o ovome sam ti pricao. Pri kasnijoj I-> U konverziji treba da dobro 'ubodes' struju koja definise 'nulti ulazni napon'. Isto ces postici uparivanjem optokaplera i odgovarajucih otpornika. Na ovo sam mislio kada sam te upitao kako ces precizno preneti jednosmernu komponentu ulaznog napona. Cak i da je jednosmerna komponenta ulaznog napona 0.0v, moramo je verno preneti, tako da napon na izlazu sklopa takodje ima jednosmernu komponentu 0.0v. Ako ne 'ubodemo' dobro struju koja definise 'nulti ulazni napon', naponu na izlazu sklopa bice superponiran neki napon greske. Btw, naponi koje ce davati merni strujni i naponski transformatori mogu sadrzati jednosmernu komponentu razlicitu od 0.0v. Ista je nula samo u idealnom slucaju. Drugi deo seme, pod pretposavkom da oba optokaplera imaju identicne karakteristike, da su OP-ovi idealani, i da otpornici idealno odgovaraju parovima iz prvog dela seme, na otporniku 1k prema masi razvijace napon Vin. Treci deo seme je neinvertujuci pojacavac sa pojacanjem 2, koji pored pojacanja sluzi i za smanjenje izlazne impedanse kola.
Ako nisam pogresio, u idealnom slucaju je Vout = 2*Vin.